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πŸ“˜ Complete Notes

Class 10 Mathematics β€’ Coordinate Geometry β€’ Chapter 7

Chapter Focus:

Coordinate Geometry connects algebra with geometry by representing points and line segments using ordered pairs of numbers.

The most important ideas in this chapter are:

1. Understanding the coordinate plane and ordered pairs
2. Finding the distance between two points
3. Finding the coordinates of a point dividing a line segment in a given ratio
4. Applying the formulas to geometric problems

πŸ—ΊοΈ Chapter Map

7.1 Coordinate Plane

A coordinate plane is formed by two perpendicular number lines. The horizontal number line is called the x-axis, while the vertical number line is called the y-axis.

The point where the two axes intersect is called the origin and is represented by (0, 0).

Cartesian Coordinate Plane
O(0,0) I II III IV x-axis y-axis
Important:
Quadrant I β†’ (+,+)
Quadrant II β†’ (βˆ’,+)
Quadrant III β†’ (βˆ’,βˆ’)
Quadrant IV β†’ (+,βˆ’)
Abscissa
The x-coordinate of a point.
Ordinate
The y-coordinate of a point.
Origin
The point (0, 0).
Ordered Pair
A point written as (x, y).
Remember: The first coordinate always gives the horizontal position and the second coordinate gives the vertical position.

7.2 Distance Formula

Consider two points A(x₁, y₁) and B(xβ‚‚, yβ‚‚) .

Draw perpendiculars from A and B to the coordinate axes. These perpendicular segments form a right triangle. The horizontal side has length |xβ‚‚ βˆ’ x₁| and the vertical side has length |yβ‚‚ βˆ’ y₁| .

Distance Between Two Points
A(x₁,y₁) B(xβ‚‚,yβ‚‚) d xβ‚‚ βˆ’ x₁ yβ‚‚ βˆ’ y₁
The distance AB is the hypotenuse of the right triangle. Therefore the Pythagorean theorem gives the distance formula.
Distance AB = √[(xβ‚‚ βˆ’ x₁)Β² + (yβ‚‚ βˆ’ y₁)Β²]

Derivation

Let the horizontal difference be xβ‚‚ βˆ’ x₁ and the vertical difference be yβ‚‚ βˆ’ y₁ .

dΒ² = (xβ‚‚ βˆ’ x₁)Β² + (yβ‚‚ βˆ’ y₁)Β²
Therefore,
d = √[(xβ‚‚ βˆ’ x₁)Β² + (yβ‚‚ βˆ’ y₁)Β²]
Example 1
Find the distance between A(2, 3) and B(6, 6) .

Using the distance formula:
d = √[(6 βˆ’ 2)Β² + (6 βˆ’ 3)Β²]
= √[4² + 3²]
= √25
= 5
Therefore, AB = 5 units.
Common Mistake: Do not forget to square both coordinate differences. The signs disappear after squaring.

πŸ“Œ Special Cases of Distance

Same x-coordinate

If x₁ = xβ‚‚, the line is vertical.
Distance = |yβ‚‚ βˆ’ y₁|
Same y-coordinate

If y₁ = yβ‚‚, the line is horizontal.
Distance = |xβ‚‚ βˆ’ x₁|
Distance from Origin

For P(x,y):
OP = √(x² + y²)

7.3 Section Formula

Suppose a point P divides the line segment joining A(x₁,y₁) and B(xβ‚‚,yβ‚‚) internally in the ratio m : n .

Internal Division in the Ratio m : n
A(x₁,y₁) P(x,y) B(xβ‚‚,yβ‚‚) m n AP : PB = m : n
P lies between A and B and divides AB internally in the ratio m:n.
P = ( mxβ‚‚ + nx₁ m + n , myβ‚‚ + ny₁ m + n )

How to Remember the Formula

Multiply the coordinate of B by m and the coordinate of A by n . Add them and divide by m+n .

Example 2
Find the coordinates of the point P that divides A(2,3) and B(8,9) internally in the ratio 2:1.
P = ( 2Γ—8 + 1Γ—2 2+1 , 2Γ—9 + 1Γ—3 2+1 )

= (6,7)
Therefore, P = (6,7) .

πŸ“ Midpoint Formula

The midpoint is the point that divides a line segment into two equal parts.

Midpoint = ( x₁ + xβ‚‚ 2 , y₁ + yβ‚‚ 2 )
Midpoint of a Line Segment
A M B AM = MB equal halves
Example 3
Find the midpoint of A(βˆ’4,2) and B(6,8) .
M = ( βˆ’4 + 6 2 , 2 + 8 2 )

= (1,5)
Therefore, M = (1,5) .

🎯 Applications of Coordinate Geometry

1. Checking Whether a Triangle is Isosceles

Find all three side lengths using the Distance Formula. If two sides are equal, the triangle is isosceles.

2. Checking Whether a Triangle is Equilateral

Calculate all three side lengths. If all three distances are equal, the triangle is equilateral.

3. Checking Right-Angled Triangle

Calculate the squares of the three side lengths. If aΒ² + bΒ² = cΒ² for the largest side c, then the triangle is right-angled.

4. Finding a Point Dividing a Segment

Use the Section Formula when a ratio is given. For equal division, use the Midpoint Formula.

5. Finding Missing Coordinates

In many coordinate geometry problems, a distance, midpoint or ratio is given and one coordinate is unknown. Substitute the known values into the appropriate formula and solve the resulting equation.

Problem-Solving Strategy:

Step 1 β†’ Write the coordinates clearly.
Step 2 β†’ Select the correct formula.
Step 3 β†’ Substitute carefully.
Step 4 β†’ Simplify step by step.
Step 5 β†’ Check whether the answer is reasonable.

✏️ Worked Examples

Example 4 β€” Distance on a Coordinate Plane
Find the distance between P(βˆ’2,4) and Q(4,βˆ’4) .
PQ = √[(4βˆ’(βˆ’2))Β² + (βˆ’4βˆ’4)Β²]
= √[6Β² + (βˆ’8)Β²]
= √(36+64)
= √100
= 10 units
Example 5 β€” Midpoint
Find the midpoint of P(5,βˆ’3) and Q(βˆ’1,7) .
M = ( 5 + (βˆ’1) 2 , βˆ’3 + 7 2 )
= (2,2)
Example 6 β€” Section Formula
Find the point dividing A(1,2) and B(7,8) in the ratio 2:1.
P = ( 2Γ—7 + 1Γ—1 3 , 2Γ—8 + 1Γ—2 3 )
= (5,6)

πŸ“‹ Formula Summary

Concept Formula / Result Use
Distance √[(xβ‚‚ βˆ’ x₁)Β² + (yβ‚‚ βˆ’ y₁)Β²] Distance between two points
Section Formula P = ( mxβ‚‚ + nx₁ m + n , myβ‚‚ + ny₁ m + n ) Internal division in m:n
Midpoint ( x₁ + xβ‚‚ 2 , y₁ + yβ‚‚ 2 ) Equal division
Origin Distance √(x² + y²) Distance of (x,y) from origin
Horizontal Distance |xβ‚‚ βˆ’ x₁| Same y-coordinate
Vertical Distance |yβ‚‚ βˆ’ y₁| Same x-coordinate

⭐ Important Results to Remember

⚑ Quick Revision

Coordinate
(x,y)
Origin
(0,0)
Quadrant I
(+,+)
Quadrant II
(βˆ’,+)
Quadrant III
(βˆ’,βˆ’)
Quadrant IV
(+,βˆ’)
Distance Formula
√[(xβ‚‚βˆ’x₁)Β²+(yβ‚‚βˆ’y₁)Β²]
Midpoint
x₁ + xβ‚‚ 2 , y₁ + yβ‚‚ 2
Section Formula
Internal ratio m:n

🎯 Exam Tips

Tip 1: Always write the correct formula before substituting the coordinates.

Tip 2: Be careful with negative coordinates.

Tip 3: Write brackets around negative values before squaring.

Example: (βˆ’4 βˆ’ 2)Β²

Tip 4: In the Section Formula, remember the opposite coefficient pairing:
mxβ‚‚ with nx₁
myβ‚‚ with ny₁

Tip 5: Simplify the square root completely whenever possible.